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4x^2+54x-58=0
a = 4; b = 54; c = -58;
Δ = b2-4ac
Δ = 542-4·4·(-58)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3844}=62$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-62}{2*4}=\frac{-116}{8} =-14+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+62}{2*4}=\frac{8}{8} =1 $
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